详解
The correct answer is 10. It’s given that the graph of x2 + x +y2 +y =1992 in the xy-plane is a circle. The equation of a circle in the xy-plane can be written in the form (x -h)2 + (y -k)2 = r2, where the coordinates of the center of the circle are (h, k) and the length of the radius of the circle is r. The term (x-h)2 in this equation can be obtained by adding the square of half the coefficient of x to both sides of the given equation to complete the square. The coefficient of x is 1. Half the coefficient of x is 12 . The square of half the coefficient of x is 14. Adding 14 to each side of (x2 + x)+ (y2+y)= 1992 yields ( x2 + x +14 )+ (y2 + y) = 1992+14 , or (x+12)2+(y2+y)=1992+14. Similarly, the term (y -k)2 can be obtained by adding the square of half the coefficient of y to both sides of this equation, which yields(x+12)2+(y2+y+14)=1992+14+14 or (x+12)2+(y2+12)2=1992+14+14. This equation is equivalent to (x+12)2+(y+12)2=100 or (x+12)2+(y+12)2=102 . Therefore, the length of the circle’sradius is 10.