OG详解-OG6 数学1 Q11

Choice A is correct. In each choice, the values of x are 2, 4, and 6. Substituting the first value of x, 2, for x in the given inequality yields y > 4(2)+8, or y > 16. Therefore, when x = 2, the corresponding value of y must be greater than 16. Of the given choices, only choice A is a table where the value of y corresponding to x = 2 is greater than 16. To confirm that the other values of x in this table and their corresponding values of y are also solutions to the given inequality, the values of x and y in the table can be substituted for x and y in the given inequality. Substituting 4 for x and 30 for y in the given inequality yields 30 > 4(4)+8, or 30 > 24, which is true. Substituting 6 for x and 41 for y in the given inequality yields 41 > 4(6)+8, or 41 > 32, which is true. It follows that for choice A, all the values of x and their corresponding values of y are solutions to the given inequality.
Choice B is incorrect. Substituting 2 for x and 8 for y in the given inequality yields 8 > 4(2)+8, or 8 >16, which is false. Choice C is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13 > 4(2)+8, or 13 > 16, which is false. Choice D is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13 > 4(2)+8, or 13 > 16, which is false.