题目详解

题目来源来自网络

题目来源:

OG详解-OG9 数学2 Q58

正确答案:410
问题反馈收藏题目
详解
The correct answer is 410. It’s given that t minutes after an initial observation, the number of bacteria in a population is60,000(2)t410​​. This expression consists of the initial number of bacteria, 60,000, multiplied by the expression 2​t410​ . The time it takes for the number of bacteria to double is the increase in the value of t that causes the expression  2​t410​ to double. Since the base of the expression 2​t410is 2, the expression 2​t410 will double when the exponent increases by 1. Since the exponent of the expression 2​t410​ is t​410​, the exponent will increase by 1 when t increases by 410.  Therefore the time, in minutes, it takes for the number of bacteria in the population to double is 410.
0
题目标记:
答对了
答错了
漏选了
题目讨论
登录 免费查看解析
还没有账号?马上注册